0=-5b^2+35+18b

Solution for 0=-5b^2+35+18b equation:

0=-5b^2+35+18b

We move all terms to the left:

0-(-5b^2+35+18b)=0

We add all the numbers together, and all the variables

-(-5b^2+35+18b)=0

We get rid of parentheses

5b^2-18b-35=0

a = 5; b = -18; c = -35;
Δ = b2-4ac
Δ = -182-4·5·(-35)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-32}{2*5}=\frac{-14}{10}
=-1+2/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+32}{2*5}=\frac{50}{10}
=5
$